Let A(1, 2), B(4, y), C(x, 6) and D(3, 5) are the vertices of a parallelogram.We know that the diagonals of parallelogram bisect each other. So,Coordinates of
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Let m be the mass of the upper ball. Let q1 represent the charge on the upper ball. For equilibrium of upper ball, it must experience an upward electric force
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Concentration of Zn2+(aq) = 0.1 + 95100=0.095 Zn2+(aq) +
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हालदार साहब जब चौराहे से गुजरे तो न चाहते हुए भी उनकी नज़र नेता जी की मूर्ति पर चली गई। मूर्ति देखकर उन्हें आश्चर्य हुआ क्योंकि मूर्ति पर सरकंडे का चश्मा लगा हुआ था। सरकंडे का चश्मा देखकर हालदार साहब को यह
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The sparrows also joined the mourning. They sat in thousands around her dead body. They didn’t chirrup. Nor did they touch the crumbs of bread thrown to them
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Given, Frequency band of radio = 7.5 MHz - 12 MHz Wavelength, λ1 = cv1 = 3 × 1087.5 × 106&
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i) F2656 nucleus contains 26 protons and, Number of neutrons = (56 - 26) = 30 neutrons Now,Mass of 26 protons = 26 x 1.007825 = 26.20345 u&n
Mass of 30 neutrons = 30 x 1.008665 = 30.25995 u
Total mass of 56 nucleons = 56.46340 u
Mass of
Fe
26
56
nucleus = 55.934939 u
∴
Mass defect,
∆
m
=
56
.
46340
-
55
.
934939
=
0
.
528461
u
Total binding energy = 0.528461 x 931.5 MeV = 492.26 MeV
Average binding energy per nucleon =
492
.
26
56
=
8
.
790
MeV
.
ii)
Bi
209
83
nucleus c
Mass of 30 neutrons = 30 x 1.008665 = 30.25995 u
Total mass of 56 nucleons = 56.46340 u
Mass of
Fe
26
56
nucleus = 55.934939 u
∴
Mass defect,
∆
m
=
56
.
46340
-
55
.
934939
=
0
.
528461
u
Total binding energy = 0.528461 x 931.5 MeV = 492.26 MeV
Average binding energy per nucleon =
492
.
26
56
=
8
.
790
MeV
.
ii)
Bi
209
83
nucleus c
PQ is the chord of the circle and PT is tangent.
We know that the tangent to a circle is perpendicular to the radius through the point of contact.
∴ ∠ OPT = 90o
Now, Given
∠ QPT = 60o
∴ ∠ OPQ = ∠OPT - ∠QPT
⇒ ∠ OPQ = 90o - 60o = 30o
In Δ OPQ,
OP= OR (Radii of the same circle)
∠ OQP = ∠ OPQ = 30o (in a triangle, equal sides have equal angles opposite to them.)
Now,
∠ OQP + ∠OPQ + ∠POQ = 180o [Angle sum property]
⇒ 30o + 30o + ∠POQ = 180o
⇒ ∠POQ = 180o - 60o = 120o
⇒ Reflex ∠POQ = 360o -120o = 240o
We know that the angle subtended by an arc of a circle a
We know that the tangent to a circle is perpendicular to the radius through the point of contact.
∴ ∠ OPT = 90o
Now, Given
∠ QPT = 60o
∴ ∠ OPQ = ∠OPT - ∠QPT
⇒ ∠ OPQ = 90o - 60o = 30o
In Δ OPQ,
OP= OR (Radii of the same circle)
∠ OQP = ∠ OPQ = 30o (in a triangle, equal sides have equal angles opposite to them.)
Now,
∠ OQP + ∠OPQ + ∠POQ = 180o [Angle sum property]
⇒ 30o + 30o + ∠POQ = 180o
⇒ ∠POQ = 180o - 60o = 120o
⇒ Reflex ∠POQ = 360o -120o = 240o
We know that the angle subtended by an arc of a circle a
The keeping of enemy at his house became the cause of stress, tension, trouble and fear for Dr. Sadao and his wife. All his servants had deserted him. The Gene
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स्वतंत्रता की नकारात्मक औ
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[Fe(CN)6]4− In the above coordination complex, iron exists in the +II oxidation state. Fe2+. Electronic configuration of Fe2+is 4s0 3d6.As CN− is a
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हर व्यक्ति को उसका प्राप्य देने का अर्थ है की जो व्यक्ति जिसका अधिकारी है, उसे वह देना ही न्याय है। इसमें जनता की भलाई की सुनिश्चितता में हर व्यक्ति को उसका वाजिब हिस्सा देना शामिल है।(Find detailed answer | clicking on this link)
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